Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 4 Quadratic Functions and Factoring - 4.3 Solve x(squared) + bx + c = 0 - 4.3 Exercises - Skill Practice - Page 257: 61

Answer

$x=3$.

Work Step by Step

Our equation (because of the formula for the area of a triangle: $0.5base\cdot height$) is: $0.5(2x+8)(x+3)=(x+4)(x+3)=42\\x^2+7x+12=42\\x^2+7x-30=0\\(x+10)(x-3)=0$ Thus $x=3$ or $x=-10$, but $x$ has to be positive, thus $x=3$.
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