Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 4 Quadratic Functions and Factoring - 4.3 Solve x(squared) + bx + c = 0 - 4.3 Exercises - Skill Practice - Page 257: 59



Work Step by Step

We know: $$ x(x+5) = 36 \\ x^2+5x-36 = 0$$ Since the coefficient of the squared term is one, we know that the expression must factor to: $$ (x\pm a)(x\pm b)$$ Here, we see that a and b must multiply to get $-36$ and add to get $5$. Thus, we find that the solution is: $$(x+9)(x-4)$$ Thus, setting each factor equal to zero, we find that the solutions are: $$ x=-9,4$$ x must be positive, so: $$x=4$$
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