Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 4 Quadratic Functions and Factoring - 4.3 Solve x(squared) + bx + c = 0 - 4.3 Exercises - Skill Practice - Page 257: 62



Work Step by Step

Our equation is: $0.5(x+2+x+6)(x)=0.5(2x+8)(x)=(x+4)(x)=32\\x^2+4x-32=0\\(x+8)(x-4)=0$ Thus $x=4$ or $x=-8$ but $x$ has to be positive, thus $x=4$.
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