Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 3 Linear Systems and Matrices - 3.8 Use Inverse Matrices to Solve Linear Systems - 3.8 Exercises - Skill Practice - Page 215: 34

Answer

Answer C

Work Step by Step

Rewrite our system of equations in matrix form: $\begin{bmatrix} 3& -5\\ -1& 2 \end{bmatrix}.\begin{bmatrix} x\\ y \end{bmatrix}=\begin{bmatrix} -26\\ 10 \end{bmatrix}$ $\begin{bmatrix} x\\ y \end{bmatrix}=\frac{1}{6-5}\begin{bmatrix} 2 & 5\\ 1&3 \end{bmatrix}.\begin{bmatrix} -26\\ 10 \end{bmatrix}$ $\begin{bmatrix} x\\ y \end{bmatrix}=\frac{1}{1}\begin{bmatrix} -2\\ 4 \end{bmatrix}$ $\begin{bmatrix} x\\ y \end{bmatrix}=\begin{bmatrix} -2\\ 4 \end{bmatrix}$ Hence, $x=-2, y=4$ The correct answer is C.
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