Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 3 Linear Systems and Matrices - 3.8 Use Inverse Matrices to Solve Linear Systems - 3.8 Exercises - Skill Practice - Page 215: 33

Answer

$x=-3, y=5$

Work Step by Step

Rewrite our system of equations in matrix form: $\begin{bmatrix} 5& 7\\ 3& 5 \end{bmatrix}.\begin{bmatrix} x\\ y \end{bmatrix}=\begin{bmatrix} 20\\ 16 \end{bmatrix}$ $\begin{bmatrix} x\\ y \end{bmatrix}=\frac{1}{25-21}\begin{bmatrix} 5 & -7\\ -3&5 \end{bmatrix}.\begin{bmatrix} 20\\ 16 \end{bmatrix}$ $\begin{bmatrix} x\\ y \end{bmatrix}=\frac{1}{4}\begin{bmatrix} -12\\ 20 \end{bmatrix}$ $\begin{bmatrix} x\\ y \end{bmatrix}=\begin{bmatrix} -3\\ 2 \end{bmatrix}$ Hence, $x=-3, y=5$
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