## Algebra 2 (1st Edition)

$x=\dfrac{\pi}{4}, \dfrac{7 \pi}{4}$
Use the Half angle formula: $\dfrac{1-\cos x}{\sin x}=\dfrac{2 -\sqrt 2}{2 \sin x}$ or, $(1-\cos x) \times (2\sin x) =(\sin x) \times (2-\sqrt 2)$ $\implies 2 (1-\cos x)=(2-\sqrt 2)$ Here, $2-2 \cos x =2-\sqrt 2$ or, $\cos x= \dfrac{\sqrt 2}{2}$ Thus, we have $x=\dfrac{\pi}{4}, \dfrac{7 \pi}{4}$