Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 14 Trigonometric Graphs, Identities, and Equations - 14.7 Apply Double-Angle and Half-Angle Formulas - 14.7 Exercises - Skill Practice - Page 960: 38

Answer

$x=0, \pi$

Work Step by Step

Use the double angle identity such as: $ \tan 2x= \dfrac{2 \tan x}{1-\tan^2 x}$ or, $ \tan x-\dfrac{2 \tan x}{1-\tan^2 x}=0$ $\implies \tan x-\tan^3 x-2 \tan x=0$ or, $- \tan x(\tan^2 x+1)=0$ This implies that $\tan x=0$ and $\tan^2 x+1=0$ Thus, we have $x=0, \pi$
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