Answer
$1-\tan^2 x$
Work Step by Step
Here, we have $\cos^2 x-\sin^2 x \ne 1$
Use the correct identity $\sin^2 x +\cos^2 x = 1$
or, $=1-\dfrac{\sin^2 x}{\cos^2 x}$
or, $=1-\tan^2 x$
Algebra 2 (1st Edition)
by Larson, Ron; Boswell, Laurie; Kanold, Timothy D.; Stiff, Lee
Published by
McDougal Littell
ISBN 10:
0618595414
ISBN 13:
978-0-61859-541-9
Chapter 14 Trigonometric Graphs, Identities, and Equations - 14.7 Apply Double-Angle and Half-Angle Formulas - 14.7 Exercises - Skill Practice - Page 960: 28
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