Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 13, Trigonometric Ratios and Functions - 13.5 Apply the Law of Sines - 13.5 Exercises - Skill Practice - Page 886: 8


No such triangle exists because $A+B \gt 180$

Work Step by Step

Law of sines: $\dfrac{\sin A}{a}=\dfrac{\sin B}{b}=\dfrac{\sin C}{c}$ Here, $A=149^{\circ}; a=7; b=10$ From the given measurements and information it can be seen that we have two sides and one angle which corresponds to $SSA$ configuration. $\dfrac{\sin 149}{7}=\dfrac{\sin B}{10} \implies B=\sin^{-1} (0.74) \approx 47.8$ Thus, no such triangle exists because $A+B \gt 180$
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