Algebra 2 (1st Edition)

Published by McDougal Littell

Chapter 13, Trigonometric Ratios and Functions - 13.1 Use Trigonometry with Right Triangles - 13.1 Exercises - Skill Practice - Page 856: 7

Answer

$\sin \theta=\dfrac{\sqrt {115}}{14}$ $\cos \theta=\dfrac{9}{14}$ $\tan \theta=\dfrac{\sqrt {115}}{9}$ $\csc \theta=\dfrac{14 \sqrt {115}}{115}$ $\sec \theta=\dfrac{14}{9}$ $\cot \theta=\dfrac{9 \sqrt{115}}{115}$

Work Step by Step

The Trigonometric Identities can be defined as: $\sin \theta=\dfrac{Opposite}{Hypotenuse}=\dfrac{\sqrt {115}}{14}$ $\cos \theta=\dfrac{Adjacent}{Hypotenuse}=\dfrac{9}{14}$ $\tan \theta=\dfrac{Opposite}{Adjacent}=\dfrac{\sqrt {115}}{9}$ $\csc \theta=\dfrac{Hypotenuse}{Opposite}=\dfrac{14}{\sqrt {115}}=\dfrac{14 \sqrt {115}}{115}$ $\sec \theta=\dfrac{Hypotenuse}{Adjacent}=\dfrac{14}{9}$ $\cot \theta=\dfrac{Adjacent}{Opposite}=\dfrac{9}{\sqrt{115}}=\dfrac{9 \sqrt{115}}{115}$

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