## Algebra 2 (1st Edition)

$\sin \theta=\dfrac{Opposite}{Hypotenuse}=\dfrac{24}{26}$ $\cos \theta=\dfrac{Adjacent}{Hypotenuse}=\dfrac{10}{26}$ $\tan \theta=\dfrac{Opposite}{Adjacent}=\dfrac{24}{10}$ $\csc \theta=\dfrac{Hypotenuse}{Opposite}=\dfrac{26}{24}$ $\sec \theta=\dfrac{Hypotenuse}{Adjacent}=\dfrac{26}{10}$ $\cot \theta=\dfrac{Adjacent}{Opposite}=\dfrac{10}{24}$
Use the Pythagorean Theorem to find the Hypotenuse. $Hypotenuse=\sqrt {24^2+10^2}=\sqrt {576+100}=26$ $\sin \theta=\dfrac{Opposite}{Hypotenuse}=\dfrac{24}{26}$ $\cos \theta=\dfrac{Adjacent}{Hypotenuse}=\dfrac{10}{26}$ $\tan \theta=\dfrac{Opposite}{Adjacent}=\dfrac{24}{10}$ $\csc \theta=\dfrac{Hypotenuse}{Opposite}=\dfrac{26}{24}$ $\sec \theta=\dfrac{Hypotenuse}{Adjacent}=\dfrac{26}{10}$ $\cot \theta=\dfrac{Adjacent}{Opposite}=\dfrac{10}{24}$