Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 12 Sequences and Series - Mixed Review of Problem Solving - Lessons 12.1-12.3 - Page 818: 1a


$a_n= 45,000 (1.035)^{n-1}$

Work Step by Step

The general formula for the nth term of a geometric series is given by $a_n= a_1r^{n-1}$ ...(1) The ratio of the successive terms is $r=1.035$ and $a_1=45,000$ Equation (1) gives: $a_n= 45,000 \times (1.035)^{n-1}$ Hence, $a_n= 45,000 (1.035)^{n-1}$
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