Answer
$a_n=2057(1.06)^{n-1}$
Tuition for $2002: \$ 3093$
Work Step by Step
The general formula for the nth term of a geometric series is given by $a_n= a_1r^{n-1}$ ...(1)
The ratio of successive terms is $r=106 %=1.06$
Here, $n=(2002-1995) +1=8$
Equation (1) gives: $a_8= 2057 \times \times (1.06)^{8-1}= 2057 \times \times (1.06)^{7} =\$ 3093$
Hence, $a_n=2057(1.06)^{n-1}$
Tuition for $2002: \$ 3093$
