## Algebra 2 (1st Edition)

Published by McDougal Littell

# Chapter 12 Sequences and Series - 12.3 Analyze Geometric Sequences and Series - 12.3 Exercises - Quiz for Lessons 12.1-12.3 - Page 817: 16

$a_n=2057(1.06)^{n-1}$ Tuition for $2002: \$ 3093$#### Work Step by Step The general formula for the nth term of a geometric series is given by$a_n= a_1r^{n-1}$...(1) The ratio of successive terms is$r=106 %=1.06$Here,$n=(2002-1995) +1=8$Equation (1) gives:$a_8= 2057 \times \times (1.06)^{8-1}= 2057 \times \times (1.06)^{7} =\$3093$ Hence, $a_n=2057(1.06)^{n-1}$ Tuition for $2002: \$ 3093\$

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