## Algebra 2 (1st Edition)

$70$
Here, we have the first term: $i_1=(1)^2+3=4$; Second Term: $i_2=(2)^2+3=7$; Third Term: $i_3=(3)^2+3=12$; Fourth Term: $i_4=(4)^2+3=19$ Last Term: $i_5=(5)^2+3=28$; Add all the terms: $S_i=4+7+12+19+28=70$