Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 12 Sequences and Series - 12.3 Analyze Geometric Sequences and Series - 12.3 Exercises - Mixed Review - Page 817: 72



Work Step by Step

Here, we have $\sum_{i=2}^{8} 1+\sum_{i=2}^{8} i^2=8-1+\sum_{i=2}^{8} i^2$ $=7+\sum_{i=2}^{8} i^2$ Use a summation formula such as: $\sum_{i=2}^{8} i^2=\dfrac{n(n+1)(2n+1)}{6}$ Now, $7+\sum_{i=2}^{8} i^2=7+\dfrac{8(8+1)(2\times 8+1)}{6}=6+204=210$
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