## Algebra 2 (1st Edition)

$x=\dfrac{7}{10}$
We are given that $\dfrac{3}{1-x}=\dfrac{10}{1}$ Re-arrange as: $10(1-x)=3$ or, $3-10=-10x$ This gives $-7=-10x$ This gives: $x=\dfrac{-7}{-10}$ Hence, $x=\dfrac{7}{10}$