Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 12 Sequences and Series - 12.3 Analyze Geometric Sequences and Series - 12.3 Exercises - Mixed Review - Page 817: 66



Work Step by Step

We are given that $9=\dfrac{4}{1+x}$ Re-arrange as: $4=9(1+x)$ or, $9x+9-4=0$ This gives $9x+5=0 \implies x=\dfrac{-5}{9}$ We need to check the solution. $9=\dfrac{4}{1+(\dfrac{-5}{9})}$ or, $9=\dfrac{4}{1-\dfrac{-5}{9}}$ or, $9=9$ Verified.
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