## Algebra 2 (1st Edition)

$x=\dfrac{-5}{9}$
We are given that $9=\dfrac{4}{1+x}$ Re-arrange as: $4=9(1+x)$ or, $9x+9-4=0$ This gives $9x+5=0 \implies x=\dfrac{-5}{9}$ We need to check the solution. $9=\dfrac{4}{1+(\dfrac{-5}{9})}$ or, $9=\dfrac{4}{1-\dfrac{-5}{9}}$ or, $9=9$ Verified.