Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 12 Sequences and Series - 12.2 Analyze Arithmetic Sequences and Series - 12.2 Exercises - Skill Practice - Page 806: 17


$a_n=36-11n$ ; $a_{20}=-184$

Work Step by Step

We know that $a_n= a_1+(n-1) d$ Here, we have $d=14-25=-11$ $a_n= (25)+(n-1) \times (-11)$ This gives: $a_n=36-11n$ $a_{20}=36-11 \times 20=-184$ Hence, $a_n=36-11n$ ; $a_{20}=-184$
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