Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 12 Sequences and Series - 12.2 Analyze Arithmetic Sequences and Series - 12.2 Exercises - Skill Practice - Page 806: 12


$a_n=-2+3n$ ; $a_{20}= 58$

Work Step by Step

We know that $a_n= a_1+(n-1) d$ Here, we have $d=4-1=3$ $a_n= 1+(n-1) \times 3$ This gives: $a_n=-2+3n$ when $n=20$, we have $a_{20}= -2+(20) \times 3=58$ Hence, $a_n=-2+3n$ ; $a_{20}= 58$
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