Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 12 Sequences and Series - 12.2 Analyze Arithmetic Sequences and Series - 12.2 Exercises - Skill Practice - Page 806: 16


$a_n=10-4n$ ; $a_{20}=-70$

Work Step by Step

We know that $a_n= a_1+(n-1) d$ Here, we have $d=2-6=-4$ $a_n= (6)+(n-1) \times (-4)$ This gives: $a_n=10-4n$ $a_{20}=10-4 \times 20=-70$ Hence, $a_n=10-4n$ ; $a_{20}=-70$
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