Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 12 Sequences and Series - 12.1 Define and Use Sequences and Series - 12.1 Exercises - Skill Practice - Page 799: 54

Answer

136

Work Step by Step

Applying the formula, we find: $$\sum _{k=1}^nk=\frac{1}{2}n\left(n+1\right)\\ \frac{1}{2}\cdot \:16\left(16+1\right) \\ 136$$
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