Answer
$50$
Work Step by Step
$\displaystyle \sum_{n=1}^{5}(n^{2}-1)=(1^{2}-1)+(2^{2}-1)+(3^{2}-1)+(4^{2}-1)+(5^{2}-1)$
$=(1-1)+(4-1)+(9-1)+(16-1)+(25-1)$
$=0+3+8+15+24$
$=50$
Algebra 2 (1st Edition)
by Larson, Ron; Boswell, Laurie; Kanold, Timothy D.; Stiff, Lee
Published by
McDougal Littell
ISBN 10:
0618595414
ISBN 13:
978-0-61859-541-9
Chapter 12 Sequences and Series - 12.1 Define and Use Sequences and Series - 12.1 Exercises - Skill Practice - Page 799: 50
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