Answer
$ 90$
Work Step by Step
$\displaystyle \sum_{k=1}^{4}3k^{2}=3\cdot 1^{2}+3 \cdot 2^{2}+3\cdot 3^{2}+3\cdot 4^{2}$
$=3 +12+27+48$
$=90$
Algebra 2 (1st Edition)
by Larson, Ron; Boswell, Laurie; Kanold, Timothy D.; Stiff, Lee
Published by
McDougal Littell
ISBN 10:
0618595414
ISBN 13:
978-0-61859-541-9
Chapter 12 Sequences and Series - 12.1 Define and Use Sequences and Series - 12.1 Exercises - Skill Practice - Page 799: 48
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