Chapter 10 Counting Methods and Probability - 10.4 Find Probabilities of Disjoint and Overlapping Events - 10.4 Exercises - Skill Practice - Page 711: 39

$\frac{5}{12}$

We have $6\times6=36$ possible outcomes. Out of these the possible ordered pairs are: $\{(1,1),(1,2),(1,4),(1,6),(2,1),(2,3),(2,5),(3,2),(3,4),(4,1),(4,3),(5,2),(5,6),(6,1),(6,5)\}$. Thus $15$ satisfy the criteria, and the probability is: $\frac{15}{36}=\frac{5}{12}$