Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 10 Counting Methods and Probability - 10.4 Find Probabilities of Disjoint and Overlapping Events - 10.4 Exercises - Skill Practice - Page 711: 39



Work Step by Step

We have $6\times6=36$ possible outcomes. Out of these the possible ordered pairs are: $\{(1,1),(1,2),(1,4),(1,6),(2,1),(2,3),(2,5),(3,2),(3,4),(4,1),(4,3),(5,2),(5,6),(6,1),(6,5)\}$. Thus $15$ satisfy the criteria, and the probability is: $\frac{15}{36}=\frac{5}{12}$
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