Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 10 Counting Methods and Probability - 10.4 Find Probabilities of Disjoint and Overlapping Events - 10.4 Exercises - Skill Practice - Page 711: 33


24%; not disjoint

Work Step by Step

$P(B) + P(A) = P(A \cap B)+ P(A \cup B)$ 16% +x%= 32% +8% Thus, $x = 24 \%$ And since the $\cap$ value isn't zero, it is not disjoint.
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