## Algebra 2 (1st Edition)

We know that the probability of rolling a 7 is $1 - P(not 7)$. Let us calculate the probability of getting a 7. Our favorable outcomes are $[(1,6)(2,5)(3,4)(4,3)(5,2)(6,1)]$ Those 6 divided by the sample space of 36 is $1/6$ $1-P(not7) = 1/6$ $P(not7 ) =5/6$