## Algebra 2 (1st Edition)

$h=2$ or $h=\frac{6}{7}$
$|7h-10|=4$ implies $7h-10=4\\7h=14\\h=2$ or $7h-10=-4\\7h=6\\h=\frac{6}{7}$. Thus $h=2$ or $h=\frac{6}{7}$ . Check: $|7\cdot2-10|=|14-10|=|4|=4$. $|7\cdot\frac{6}{7}-10|=|6-10|=|-4|=4$. Thus both are correct solutions.