Algebra 1

$y=.5x^2$ vertex: $x=-b/2a$ $x = 0/2*.5$ $x = 0$ $y=.5*x^2$ $y=.5*0^2$ $y = .5*0$ $y=0$ One other point on the graph $x=2$ $y=.5*2^2$ $y=.5*4$ $y=2$ The blue line is the axis of symmetry.