Answer
Find the axis of symmetry.
Find the vertex.
Find one other point on the curve.
Plot the point that has the same difference from the axis of symmetry as the point we just found.
Work Step by Step
$y=2x^2+5$
axis of symmetry:
$x=-b/2a$
$x=0/2*2$
$x=0$
vertex:
$y=2x^2+5$
$y=2*0^2+5$
$y=2*0+5$
$y=5$
One other point on the curve:
$x=1$
$y=2x^2+5$
$y=2*1^2+5$
$y=2*1+5$
$y=7$
$1-0=1$, so we also know $(-1,7)$ is a point on the curve.
