Answer
Please see the graph.
Work Step by Step
$y=-2x^2-1$
vertex:
$x = -b/2a$
$x = -0/2*-2$
$x = 0/-4 = 0$
$y=-2*0^2-1$
$y=-2*0-1$
$y=0-1 = -1$
One other point on the curve:
$x = 1$
$y=-2*1^2-1$
$y=-2*1-1$
$y=-2-1 = -3$
Algebra 1
by Hall, Prentice
Published by
Prentice Hall
ISBN 10:
0133500403
ISBN 13:
978-0-13350-040-0
Chapter 9 - Quadratic Functions and Equations - Mid-Chapter Quiz - Page 560: 6
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