## Algebra 1

t $\approx$ ± 2.8
$\frac{1}{2}$$t^{2} - 4 = 0 First, add 4 to both sides: \frac{1}{2}$$t^{2}$ - 4 + 4 = 0 + 4 $\frac{1}{2}$$t^{2} = 4 Now, divide both sides by \frac{1}{2} (which is the same as multiplying by 2): 2(\frac{1}{2}$$t^{2}$) = 2(4) $t^{2}$ = 8 Now, take the square root of both sides: $\sqrt t^{2}$ = $\sqrt 8$ t = ± 2$\sqrt 2$ $\approx$ ± 2.8