Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 9 - Quadratic Functions and Equations - 9-3 Solving Quadratic Equations - Practice and Problem-Solving Exercises: 46

Answer

t $\approx$ ± 2.8

Work Step by Step

$\frac{1}{2}$$t^{2}$ - 4 = 0 First, add 4 to both sides: $\frac{1}{2}$$t^{2}$ - 4 + 4 = 0 + 4 $\frac{1}{2}$$t^{2}$ = 4 Now, divide both sides by $\frac{1}{2}$ (which is the same as multiplying by 2): 2($\frac{1}{2}$$t^{2}$) = 2(4) $t^{2}$ = 8 Now, take the square root of both sides: $\sqrt t^{2}$ = $\sqrt 8$ t = ± 2$\sqrt 2$ $\approx$ ± 2.8
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.