## Algebra 1

m = ±$\frac{1}{6}$
3$m^{2}$ - $\frac{1}{12}$ = 0 Add $\frac{1}{12}$ to both sides: 3$m^{2}$ - $\frac{1}{12}$ + $\frac{1}{12}$ = 0 + $\frac{1}{12}$ 3$m^{2}$ = $\frac{1}{12}$ Divide both sides by 3: (3$m^{2}$) $\div$ 3 = $\frac{1}{12}$ $\div$ 3 $m^{2}$ = $\frac{1}{36}$ Take the square root of both sides to get m by itself: $\sqrt (m^{2})$ = $\sqrt \frac{1}{36}$ m = ±$\frac{\sqrt 1}{\sqrt 36}$ = ±$\frac{1}{6}$