## Algebra 1

± $\frac{3}{7}$
49$p^{2}$ - 16 = -7 Add 16 to both sides: 49$p^{2}$ - 16 + 16 = -7 + 16 49$p^{2}$ = 9 Divide both sides by 49: $\frac{49p^{2}}{49}$ = $\frac{9}{49}$ $p^{2}$ = $\frac{9}{49}$ Take the square root of both sides to get p by itself: $\sqrt p^{2}$ = $\sqrt \frac{9}{49}$ p = ± $\frac{3}{7}$