## Algebra 1

Published by Prentice Hall

# Chapter 8 - Polynomials and Factoring - Chapter Review - 8-5 and 8-6 Factoring Quadratic Trinomials - Page 525: 57

5(g+1)(g+2)

#### Work Step by Step

Given the polynomial $5g^{2}$ + 15g + 10 We see that the terms have a common factor of 5 so we factor out a 5. 5($g^{2}$ + 3g + 2) *** We break of the middle term into two factors that add to give +3 and multiply to give +2. The two numbers are +2 and +1. 5($g^{2}$ + g + 2g + 2) We take the GCD of the first two and the GCD of the last two terms. 5(g(g+1) +2(g +1)) We take (g +1) and factor it out which gives us. 5(g+1)(g+2)

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