#### Answer

(2v-1)(5v+8)

#### Work Step by Step

Given the polynomial
$10v^{2}$ + 11v - 8
*** We break of the middle term into two factors that add to give +11 and multiply to give -80. The two numbers are +16 and -5.
$10v^{2}$ - 5v + 16v - 8
We take the GCD of the first two and the GCD of the last two terms.
5v(2v-1) +8(2v-1)
We take (2v-1) and factor it out which gives us.
(2v-1)(5v+8)