## Algebra 1

Given the polynomial $10v^{2}$ + 11v - 8 *** We break of the middle term into two factors that add to give +11 and multiply to give -80. The two numbers are +16 and -5. $10v^{2}$ - 5v + 16v - 8 We take the GCD of the first two and the GCD of the last two terms. 5v(2v-1) +8(2v-1) We take (2v-1) and factor it out which gives us. (2v-1)(5v+8)