Answer
(x+2)(x+19)
Work Step by Step
Given the polynomial
$x^{2}$ + 21x + 38
*** We break of the middle term into two factors that add to give +21 and multiply to give +38. The two numbers are +19 and +2.
$x^{2}$ + 2x + 19x + 38
We take the GCD of the first two and the GCD of the last two terms.
x(x+2) +19(x+2)
We take (x+2) and factor it out which gives us.
(x+2)(x+19)
