Algebra 1

Given the polynomial $x^{2}$ + 21x + 38 *** We break of the middle term into two factors that add to give +21 and multiply to give +38. The two numbers are +19 and +2. $x^{2}$ + 2x + 19x + 38 We take the GCD of the first two and the GCD of the last two terms. x(x+2) +19(x+2) We take (x+2) and factor it out which gives us. (x+2)(x+19)