## Algebra 1

Published by Prentice Hall

# Chapter 8 - Polynomials and Factoring - 8-8 Factoring by Grouping - Standardized Test Prep - Page 521: 51

#### Answer

5r(r+3)($2r^{2}$+1)

#### Work Step by Step

Given the polynomial $10r^{4}$ + $30r^{3}$ + $5r^{2}$ + 15r We see that the terms have a common factor of 5r so we factor out a 5r. 5r($2r^{3}$ + $6r^{2}$ + r + 3) We take the GCD of the first two and the GCD of the last two terms. 5r ($2r^{2}$(r+3)+1(r+3)) We take (r+3) and factor it out which gives us. 5r(r+3)($2r^{2}$+1)

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.