Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 8 - Polynomials and Factoring - 8-8 Factoring by Grouping - Standardized Test Prep - Page 521: 47


Option D 6(5z-2)($z^{2}$+4)

Work Step by Step

Given the polynomial $30z^{3}$ - $12z^{2}$ + 120z- 48 We see that the three terms have a common factor of 6 so we factor out a 6. 6($5z^{3}$ - $2z^{2}$ + 20z- 8) We take the GCD of the first two and the GCD of the last two terms. 6($z^{2}$(5z-2) +4(5z-2)) We take (5z-2) and factor it out which gives us. 6(5z-2)($z^{2}$+4)
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