Algebra 1

Published by Prentice Hall

Chapter 8 - Polynomials and Factoring - 8-8 Factoring by Grouping - Standardized Test Prep - Page 521: 48

Answer

Option F $2x^{11}$

Work Step by Step

$2x^{3} \times x^{8}$ According to the exponent rule for multiplication $x^{a} \times x^{b} = x^{a+b}$ Therefore in this example a= 3 and b= 8 $x^{a+b}$ $x^{3+8}$ $x^{11}$ Therefore $2x^{3} \times x^{8}$ = $2x^{11}$

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