## Algebra 1

Published by Prentice Hall

# Chapter 8 - Polynomials and Factoring - 8-7 Factoring Special Cases - Mixed Review - Page 516: 69

#### Answer

4$h^{2}$

#### Work Step by Step

Given the polynomial $16h^{4}$ - $12h^{3}$ - $36h^{2}$ We find the factors of all the terms in the polynomial. Factors of 16: 1,2, 4, 8, 16 $1 \times 16 ; 2 \times 8, 4 \times 4$ Factors of 12: 1 , 2, 3, 4, 6, 12 $1 \times 12 ; 2 \times 6 ; 3 \times 4$ Factors of 36: 1, 2, 3, 4, 6, 9, 12, 18, 36 $1 \times 36 ; 2 \times 18 ; 3 \times 12 ; 4 \times 9 ; 6 \times 6$ All the three terms have the factor of 4$h^{2}$ and thus the greatest common factor is 4$h^{2}$.

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