Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 8 - Polynomials and Factoring - 8-7 Factoring Special Cases - Mixed Review: 66

Answer

(3x-5)(4x-7)

Work Step by Step

Given the polynomial $12x^{2}$ - 41x + 35 *** We break of the middle term into two factors that add to give -41 and multiply to give +420. The two numbers are -20 and -21. $12x^{2}$ - 20x - 21x + 35 We take the GCD of the first two and the GCD of the last two terms. 4x(3x-5) - 7(3x-5) We take (3x-5) and factor it out which gives us. (3x-5)(4x-7)
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