Answer
(y-8)(y-8)
Work Step by Step
Given the polynomial
$y^{2}$ - 16y + 64
*** We break of the middle term into two factors that add to give -16 and multiply to give +64. The two numbers are -8 and -8.
$y^{2}$ - 8y - 8y + 64
We take the GCD of the first two and the GCD of the last two terms.
y(y-8) -8(y-8)
We take (y-8) and factor it out which gives us.
(y-8)(y-8)
