## Algebra 1

Given the polynomial $y^{2}$ - 16y + 64 *** We break of the middle term into two factors that add to give -16 and multiply to give +64. The two numbers are -8 and -8. $y^{2}$ - 8y - 8y + 64 We take the GCD of the first two and the GCD of the last two terms. y(y-8) -8(y-8) We take (y-8) and factor it out which gives us. (y-8)(y-8)