# Chapter 8 - Polynomials and Factoring - 8-7 Factoring Special Cases - Lesson Check: 8

(2x+1)(x+6)

#### Work Step by Step

Given the polynomial $2x^{2}$ + 13x + 6 *** We break of the middle term into two factors that add to give +13 and multiply to give +12. The two numbers are +12 and +1. $2x^{2}$ + 1x + 12x + 6 We take the GCD of the first two and the GCD of the last two terms. x(2x+1) + 6(2x+1) We take (2x+1) and factor it out which gives us. (2x+1)(x+6)

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