Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 8 - Polynomials and Factoring - 8-7 Factoring Special Cases - Lesson Check: 2

Answer

(3q+2)(3q+2)

Work Step by Step

$9q^{2}$+12q+4 Using the rule of $a^{2}$+2ab+$b^{2}$= $(a+b)^{2}$ In this case, the a= 3q and b= 2 as substituting these gives us the original polynomial $a^{2}$+2ab+$b^{2}$ $(3q)^{2}$+2(3q)(2)+$2^{2}$ $9q^{2}$+12q+4 Thus: $9q^{2}$+12q+4 = $(3q+2)^{2}$ = (3q+2)(3q+2)
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