Answer
(3q+2)(3q+2)
Work Step by Step
$9q^{2}$+12q+4
Using the rule of
$a^{2}$+2ab+$b^{2}$= $(a+b)^{2}$
In this case, the a= 3q and b= 2 as substituting these gives us the original polynomial
$a^{2}$+2ab+$b^{2}$
$(3q)^{2}$+2(3q)(2)+$2^{2}$
$9q^{2}$+12q+4
Thus:
$9q^{2}$+12q+4
= $(3q+2)^{2}$
= (3q+2)(3q+2)
