Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 8 - Polynomials and Factoring - 8-7 Factoring Special Cases - Lesson Check: 3

Answer

(p-6)(p+6)

Work Step by Step

We use the formula for the difference of squares to apply to this question. The difference of squares formula is: $(a-b) (a+b) = a^{2} - b^{2}$ $p^{2} - 36$ We rewrite it in $a^{2} - b^{2}$ form $p^{2} - 6^{2}$ In the given formula let p represents a and 6 represents b. $a^{2} - b^{2}$ = (a-b) (a+b) $p^{2} - 6^{2}$ =(p-6)(p+6)
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