## Algebra 1

$10^{10}$
Given : $\frac{10^{7}\times10^{0}}{10^{-3}}$ This becomes : $\frac{10^{7+0}}{10^{-3}}$ (since $a^{m}\times a^{n}=$ $a^{m+n}$) This becomes : $10^{7-(-3)}$ (since $\frac{a^{m}}{a^{n}} =$ $a^{m-n}$) Hence, final result : $10^{10}$