## Algebra 1

$\frac{2}{27}$
=$\frac{(\frac{1}{4})^{-2}}{(\frac{1}{6})^{-3}}$ =$\frac{\frac{1}{4^{-2}}}{\frac{1}{6^{-3}}}$ =$\frac{4^{2}}{6^{3}}$ =$\frac{16}{216}$ =$\frac{2}{27}$