Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 7 - Exponents and Exponential Functions - 7-5 Division Properties of Exponents - Practice and Problem-Solving Exercises: 73

Answer

$\frac{2}{27}$

Work Step by Step

=$\frac{(\frac{1}{4})^{-2}}{(\frac{1}{6})^{-3}}$ =$\frac{\frac{1}{4^{-2}}}{\frac{1}{6^{-3}}}$ =$\frac{4^{2}}{6^{3}}$ =$\frac{16}{216}$ =$\frac{2}{27}$
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