Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 7 - Exponents and Exponential Functions - 7-5 Division Properties of Exponents - Practice and Problem-Solving Exercises: 78

Answer

$\frac{2b^{5}}{3a}$

Work Step by Step

=$\frac{(6a^{3})(8b^{4})}{(2a^{4}(36b^{-1})}$ =$\frac{48a^{3}b^{4}}{72a^{4}b^{-1}}$ =$\frac{48a^{3-3}b^{4+1}}{72a^{4-3}b^{-1+1}}$ =$\frac{48b^{5}}{72a}$ =$\frac{2b^{5}}{3a}$
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