Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 7 - Exponents and Exponential Functions - 7-2 Scientific Notation - Practice and Problem-Solving Exercises: 51

Answer

The answer is $(t+3)^{\frac{6}{5}}$

Work Step by Step

to solve for $(t+3)^{\frac{4}{5}}$ $\times$ $(t+3)^{\frac{2}{5}}$ . Since the base is same and the exponents are both positive we can add the two exponents so $\frac{4}{5}$ + $\frac{2}{5}$ = $\frac{6}{5}$ . Therefore, the simplified answer is $(t+3)^{\frac{6}{5}}$
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