## Algebra 1

The answer is $(t+3)^{\frac{6}{5}}$
to solve for $(t+3)^{\frac{4}{5}}$ $\times$ $(t+3)^{\frac{2}{5}}$ . Since the base is same and the exponents are both positive we can add the two exponents so $\frac{4}{5}$ + $\frac{2}{5}$ = $\frac{6}{5}$ . Therefore, the simplified answer is $(t+3)^{\frac{6}{5}}$