Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 7 - Exponents and Exponential Functions - 7-2 Scientific Notation - Practice and Problem-Solving Exercises - Page 425: 50


The answer is $\frac{1}{(a+b)}$

Work Step by Step

to solve for $(a+b)^{2}$$\times$$(a+b)^{-3}$ it becomes $\frac{(a+b)^{2}}{(a+b)^{3}}$. Since the base is same and the exponent is larger on the denominator, you subtract the exponent of the numerator from the denominator and so 3-2 equals which means you have only one (a+b) on the denominator and 1 on the numerator. Therefore, the simplified answer is $\frac{1}{(a+b)}$
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